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French Open | Šwiateková – Keninová 6: 4, 6: 1, Polish teenager conquered Paris! Kvitová’s conqueror had no chance

Famous, amazing, unique! What attribute to choose for the sensational performance of the young Polish tennis player Iga Šwiateková at this year’s French Open? The nineteen-year-old native from Warsaw made her sensational campaign to the premiere grand slam triumph, in Saturday’s final on the clay clay in Paris she did not even have the semi-final winner Petra Kvitová and Australian Open champion Sofia Keninová from the USA. In less than an hour and a half, he celebrated the Polish miracle in sets 6: 4 and 6: 1. During the whole tournament, the unattached Šwiateková did not lose a single set!

Gonzalo Fuentes, Reuters

Šwiateková became the youngest winner of the tournament since 1992, when 18-year-old Monika Selešová won. She was the first Polka in history to dominate the Grand Slam singles. The winner collected a check for 1.6 million euros (approximately 43 million crowns) and will move from 53rd to 17th place in the WTA rankings.

Both finalists in the tournament passed over the Czech opponent. Tournament four Keninová stopped Petra Kvitová in the semifinals, Šwiateková in last year’s finalist Markéta Vondroušová in the first round.

French Cup results at the French Open:
BIKE COMPETITION RESULT
finals Keninová (USA) 6:4, 6:1
semifinal Podoroská (Arg.) 6:2, 6:1
quarterfinals Trevisanová (Ita.) 6:3, 6:1
round of 16 Halepová (ROU) 6:1, 6:2
Round 3 Bouchardová (CAN) 6:3, 6:2
Round 2 Hsieh (Western.) 6:1, 6:4
1. round Vondroušová (CZE) 6:1, 6:2

Keninová and Šwiateková have not yet met on the WTA circuit. They played together in Paris in juniors four years ago and Polka was also happy with the victory.

Juniors:
Singles – Final:
Stricker (7-Switzerland) – Riedi (8-Switzerland) 6: 2, 6: 4.
Doubles – Final:
Cobolli, Stricker (3-It./Švýc.) – Oliveira, Rodrigues (8-Braz.) 6: 2, 6: 4.
Juniors:
Singles – Final:
Jacquemotova (3-Fr.) – Carayevova (RUS) 4: 6, 6: 4, 6: 2.
Doubles – Final:
Alvisiova, Pigatova (It.) – Bondarenko, Schneider (5-Rus.) 7: 6 (7: 3), 6: 4.

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