Home » today » News » Florida beats New York in number of infections

Florida beats New York in number of infections

ORLANDO, Florida, USA – Florida overtook New York over the weekend as the state with the second-highest number of coronavirus cases in the United States, after more than 9,300 new infections were reported in the southern entity on Sunday. , along with 78 additional deaths.
The 423,855 cases of COVID-19 in Florida as of Sunday are only surpassed by 453,659 in California, the most populous state in the country with 39.5 million inhabitants, almost double the Florida’s 21.4 million. Texas is the second with more inhabitants, followed by Florida and New York in third and fourth place.
New York, which at one point became the epicenter of the outbreak in the United States, has 411,736 cases. 19.4 million inhabitants live in the state.
9,344 new cases were reported in Florida on Sunday, down from other days last week, but Sunday reports are usually lower due to fewer workers reporting data or labs examining samples. The average age of coronavirus patients in the state is 40 years.

It might interest you:

Almost 3.4 million Florida residents have been tested for the virus. Tests on new cases Sunday tested positive at an 11% rate, according to the state Department of Health.
The department recorded 781 COVID-19 deaths last week, with an average of 126 deaths per day announced on Sunday, a slight decrease from the weekly average of 127 deaths per day released on Saturday.

In Florida, a total of 5,972 people have died from this disease as of Sunday, according to the state Department of Health. There have been 8,951 coronavirus-related hospitalizations in Florida as of Sunday.

Leave a Comment

This site uses Akismet to reduce spam. Learn how your comment data is processed.