Miomir Kecmanovic upset world number four Alexander Zverev in the second round of the Abierto Mexicano Telcel presentado por HSBC in Acapulco on Wednesday, earning the first Top 5 win of his career. Kecmanovic defeated Zverev 6-3, 6-7(3), 7-6(4), according to the ATP Tour.
The match marked the fourth time the two players have faced each other, with Zverev previously holding a 2-1 advantage in the head-to-head record, according to Tennistonic. However, their previous encounters on hard courts were evenly split at 1-1.
Zverev, a former champion in Acapulco, entered the tournament with a 3-3 record in second-round matches at the event. He had won six of his seven tour-level matches so far in 2026, as noted by Flashscore. Kecmanovic, a former quarterfinalist in Acapulco, was 1-2 in second-round matches prior to Wednesday’s victory.
Prior to facing Kecmanovic, Zverev secured a first-round win against Frenchman Courentin Moutet with a score of 6-2, 6-4. The tournament is taking place amid unrest in the region, according to reports.
Elsewhere in Acapulco, other matches concluded on Wednesday. Yannick Hanfmann defeated Camilo Ugo Carabelli 6-4, 6-3, advancing to the next round. In Dubai, Daniil Medvedev defeated Stan Wawrinka 6-2, 6-3, and Felix Auger-Aliassime overcame John Mpetshi Perricard 6-4, 6-4.
The match between Zverev and Kecmanovic was scheduled to initiate around 1:00 a.m. Local time. Kecmanovic had previously never defeated a top-five player, holding an 0-11 record in such matches before Wednesday’s result.
